The following two compounds `I` and `II` can be distinguished by using reagent
" "
(a) aq. `NaHCO_(3)` " " (b) Neutral `FeCl_(3)`
(c ) Blue litmus solution " " `Na` metal " " (e) `HCl//ZnCl_(2)` anhydrous

Options

A. `a` or c`
B. `b` or `e`
C. `d` or `e`
D. `c` or `d`

Answer

B

Explanation

(a) Both give the test with `aq`. `NaHCO_(3)` because both have `-COOH` group and acidic hydrogen.
(b) `II` give `+ ve` test with neutral `FeCl_(3)` due to presence of phenolic `-OH` group, but `(I)` does not.
( c) In`(I)` and `(II)` acidic hydrogen atom is present so both give `+ve` test with blue litmus solution.
(d) In `(I)` and `(II)` acidic hydrogen atom is present so both give +`ve` test with `Na` metal.
(e) `(I)` give `+ve` test with `HCl//ZnCl_(2)` due to presence of aliphatic alcoholic group, but `(II)` does not.