Treatment of `(CH_(3))_(3)C CH(OH)CH_(3)` with conc, hydrochloric acid gives two isomeric alkyl chorides. What are there two products?

Explanation

To solve the problem of determining the two isomeric alkyl chlorides formed from the treatment of `(CH₃)₃C CH(OH)CH₃` with concentrated hydrochloric acid, we can follow these steps:

### Step 1: Identify the structure of the starting compound
The given compound is `(CH₃)₃C CH(OH)CH₃`, which can be represented as:
```
CH₃
|
CH₃-C-CH(OH)-CH₃
...