2,2-Dechloro-3-methyl butane on hydrolysis forms

Options

A. Diethyl ketone
B. methyl isopropyl ketone
C. 3-methyl butance 2,3 diol
D. 2-methyl butane 2,3 doil

Answer

To solve the problem of what 2,2-Dichloro-3-methylbutane forms upon hydrolysis, we can follow these steps:

### Step 1: Understand the Structure
2,2-Dichloro-3-methylbutane has the following structure:
- The butane chain has a total of four carbon atoms.
- There are two chlorine atoms attached to the second carbon (C-2).
- There is a methyl group attached to the third carbon (C-3).

### Step 2: Hydrolysis Reaction
When 2,2-Dichloro-3-methylbutane undergoes hydrolysis, it reacts with water (or an alcohol) to replace the chlorine atoms with hydroxyl (OH) groups.

### Step 3: Formation of Carbocation
The hydrolysis begins with the formation of a carbocation. The chlorine atoms are good leaving groups, and when one of them leaves, it generates a secondary carbocation at the C-2 position. This carbocation is stabilized by the inductive effect of the neighboring carbon atoms.

### Step 4: Nucleophilic Attack
Water (acting as a nucleophile) attacks the carbocation. The oxygen in water has a partial negative charge and will bond with the positively charged carbon atom (C-2). This results in the formation of an intermediate where the OH group is attached to C-2.

### Step 5: Deprotonation
The intermediate formed has a positively charged hydroxyl group (OH2+). A proton (H+) is removed from this intermediate, resulting in the formation of a neutral alcohol.

### Step 6: Final Product
The final product of this hydrolysis reaction is 2,3-Dimethylbutan-2-ol, which can also be referred to as 2,3-diol due to the presence of two hydroxyl groups on the second and third carbons.

### Conclusion
Thus, the hydrolysis of 2,2-Dichloro-3-methylbutane yields **2,3-Dimethylbutan-2-ol**.

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