STATEMENT-1: Tertiary butyl bromide and sodium ethoxide will react to form only ether.
and
STATEMENT-2: Ether are prepared by the reaction of alkoxides with alkyl halides.

Options

A. Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for statement-5
B. Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-5
C. Statement-1 is True, Statement-2 is False
D. Statement-1 is False, Statement-2 is True

Answer

To analyze the statements given in the question, we can break down the solution step by step.

### Step 1: Analyze Statement 1
**Statement 1:** Tertiary butyl bromide and sodium ethoxide will react to form only ether.

- Tertiary butyl bromide (C4H9Br) is a tertiary alkyl halide. When it reacts with sodium ethoxide (C2H5O-), two possibilities arise:
1. **Formation of Ether:** Sodium ethoxide acts as a nucleophile and attacks the carbon atom attached to the bromine, leading to the formation of ether (C2H5O-C4H9) and the release of bromide ion (Br-).
2. **Formation of Alkene:** The bromine can leave first, forming a stable tertiary carbocation (C4H9+). Sodium ethoxide can then act as a base, abstracting a proton from the adjacent carbon, leading to the formation of an alkene (C4H8) and possibly ether as well.

Thus, since both ether and alkene can be formed, **Statement 1 is false.**

### Step 2: Analyze Statement 2
**Statement 2:** Ethers are prepared by the reaction of alkoxides with alkyl halides.

- This statement is true. The general reaction for preparing ethers involves an alkoxide (RO-) reacting with an alkyl halide (R'X). The alkoxide acts as a nucleophile, attacking the carbon atom of the alkyl halide, leading to the formation of ether (R-O-R') and the release of a halide ion (X-).

### Conclusion
- **Statement 1 is false.**
- **Statement 2 is true.**

### Final Answer
The correct option is: **Statement 1 is false and Statement 2 is true.**

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