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cosec3i=sec59^(@)...

cosec3i=sec59^(@)

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Without using trigonometric tables, evaluate : (i) cos 48^@-sin42^@ (ii) cosec31^@-sec59^@ (iii) cot 34^@-tan56^@ (iv) cos^2 13^@-sin^2 77^@

Evaluate:(iv) Cosec31^@-Sec59^@

Evaluate: cosec31^(@)-sec59^(@)

Evaluate : co s e c31^@-sec59^@ .

Without using Trigonometric Tables evaluate the following :- (tan 48)/(2cot42^@)+(3cosec31^@)/(sec59^@)-(cos69^@)/(2sin21^@)+2tan23^@tan37^@tan67^@tan53^@ .

" (1) sec^(2)A+cosec^(2)A=sec^(2)A*cosec^(2)A

Prove that sec^(2)A+"cosec"^(2)A=sec^(2)A"cosec"^(2)A .

Evaluate : (i) (sin18^@)/(cos72^@) (ii) (tan26^@)/(cot64^@) (iii) cos48^@-sin42^@ (iv) c o s e c 31^@sec59^@

Evaluate : cosec 31^(@) - sec 59^(@)

Evaluate cosec 31^(@) -sec 59^(@)