Let `a` & `b` be two non-zero perpendicular vectors. If a vector `vecx` satisfying the equation `vecx xxvecb=veca` is `vecx = betab - (a xx b)/|vecb|^2` then `beta` can be

Let veca and vecb be two non- zero perpendicular vectors. A vector vecr satisfying the equation vecr xx vecb = veca can be

Let veca and vecb be two non- zero perpendicular vectors. A vector vecr satisfying the equation vecr xx vecb = veca can be

Let veca and vecb be two non- zero perpendicular vectors. A vector vecr satisfying the equation vecr xx vecb = veca can be

Let veca and vecb be two non- zero perpendicular vectors. A vector vecr satisfying the equation vecr xx vecb = veca can be

Let vec aa n d vec b be two non-zero perpendicular vectors. A vecrtor vec x satisfying the equation vec x xx vec b= vec a is vecx= beta vecb-1/|b|^2 vecaxx vecb then beta can be

Let vec aa n d vec b be two non-zero perpendicular vectors. A vecrtor vec x satisfying the equation vec x xx vec b= vec a is vecx= beta vecb-1/|b|^2 vecaxx vecb then beta can be

Let vecp,vecq, vecr be three mutually perpendicular vectors of the same magnitude. If a vector vecx satisfies the equation vecpxx{vecx-vecq)xxvec p}+vecq xx{vecx-vecr)xxvecq}+vecrxx{vecx-vecp)xxvecr}=vec0 , then vecx is given by

Let vecp,vecq, vecr be three mutually perpendicular vectors of the same magnitude. If a vector vecx satisfies the equation vecpxx{vecx-vecq)xxvec p}+vecq xx{vecx-vecr)xxvecq}+vecrxx{vecx-vecp)xxvecr}=vec0 , then vecx is given by