" (iv) "ax^(2)-2abx=0

What does the equation (a-b)(x^(2)+y^(2))-2abx=0 become when the origin is shifted to the point ((ab)/(a-b),0) without rotation of axes ?

The roots of the equation 2a^(2)x^(2) - 2abx + b^(2) = 0 when a lt 0 and b gt 0 are :

Solve the following quadratic equation : 6a^(2) x^(2) - 7abx - 3b^(2) = 0

What does the equation (a-b)(x^(2)+y^(2))-2abx=0 become if the origin is shifted to the point ((ab)/(a-b),0) without rotation?

If the tangents of the angles A and B of triangle ABC satisfy the equation abx^(2)-c^(2)x+ab=0 , then

If the tangents of the angles A,B of a Delta ABC... satisfy the equation abx^(2)-c^(2)x+ab=0 then

Solve the following quadratic equation by the method of completing square:(v) a^2x^2-3abx+2b^2=0

If alpha,beta are the roots of ax^(2)+bx+c=0 then those of ax^(2)+2bx+4c=0 are