In Delta ABC,(a)/(cos A)=(b)/(cos B)=(c)/(cos C);" if "b=2," then the area of the triangle is "

In Delta ABC, (b-a cos C)/(c-a cos B)=

In a Delta ABC with usual notations, if (a)/(cos A)=(b)/(cos B)=(c )/(cos C) , then the triangle is :

In a triangle ABC, if (cos A)/(a) =(cos B)/(b ) =(cos C)/(c) and the side a=2, then the area of the triangle is-

In Delta ABC,(cos C+cos A)/(c+a)+(cos B)/(b)=

In Delta ABC , a( b cos C - c cos B) =

In a triangle ABC,if (cos A)/(a)=(cos B)/(b)=(cos C)/(c) and the side a=2 then area of triangle is and the side a=2

In Delta ABC, (cos C+ cos A)/(c+a)+(cos B)/b=

If in a Delta ABC,(cos A)/(a)=(cos B)/(b)=(cos C)/(c), then find the measures of angles A,B,C.