xy+y^(2)=tan(x+y)

y^(2)+xy=tan(x+y) then find (dy)/(dx)=?

xy = tan (x + y)

Find (dy)/(dx) if xy^2 + y^2 = tan x + y

(sin x + sin y) / (sin x-sin y) = tan ((x + y) / (2)) * cot ((xy) / (2))

The number of pairs of integer (x,y) that satisfy the follownig two equations {(cos (xy)=x),(tan(xy)=y):}

If cos ^ (- 1) x + cos ^ (- 1) y = (pi) / (2), tan ^ (- 1) x-tan ^ (- 1) y = 0 then x ^ (2) + xy + y ^ (2) =

The solution of (dy)/(dx)=((x-1)^(2)+(y-2)^(2)tan^(-1)((y-2)/(x-1)))/((xy-2x-y+2)tan^(-1)((y-2)/(x-1))) is equal to

Find the general solution of the differential equation : (dx)/(dy)=(y tan y- x tan y - xy)/( y tan y) .

Write down the conditioni under which tan^-1 x + tan^-1 y = tan^-1 (x+y)/(1-xy), x, y in r .

If x:y::5:2, then (x ^(2) - xy + y ^(2))/( x ^(2) + xy + y ^(2)) = ?