`(z-alpha)/(z+alpha)` is purely imaginary and `|z|=82` then `|alpha|` is:

Let (z-alpha)/(z+alpha) is purely imaginary and |z|=2, alpha in RR then alpha is equal to (A) 2 (B) 1 (C) sqrt2 (D) sqrt3

Suppose a in R and z in C. "If" |z| = 2 and (z-alpha)/(z+alpha) is purely imaginary, then 1.25 |alpha| is equal to ____________.

if z-bar(z)=0 then z is purely imaginary

If the ratio (1-z)/(1+z) is purely imaginary, then

If the number (z-1)/(z+1) is purely imaginary, then

If z is purely imaginary ; then arg(z)=+-(pi)/(2)

The set of all alpha in R for which w = (1+(1-8 alpha)z)/(1-z) is a purely imaginary number, for all z in C , satisfying |z| = 1 and Re(z) ne 1 , is

Consider two complex numbers alphaa n dbeta as alpha=[(a+b i)//(a-b i)]^2+[(a-b i)//(a+b i)]^2, where a ,b , in R and beta=(z-1)//(z+1), w here |z|=1, then find the correct statement: both alphaa n dbeta are purely real both alphaa n dbeta are purely imaginary alpha is purely real andbeta is purely imaginary beta is purely real and alpha is purely imaginary

if the number (z-2)/(z+2) is purely imaginary then find the value of |z|