Rate constant for a reaction `H_(2) + I_(2) rarr 2HI` is `49`, then rate constant for reaction `2HI rarr H_(2) + I_(2)` is

If the equilibrium constant of the reaction 2HI hArrH_(2) + I_(2) is 0.25 , then the equilibrium constant of the reaction H_(2) + I_(2)hArr2HI would be

For the reaction H_(2)(g)+I_(2)(g) hArr 2HI(g) , the rate of reaction is expressed as

For the reaction H_(2)(g)+I_(2)(g) hArr 2HI(g) , the rate of reaction is expressed as

The equilibrium constant at 717 K for the reaction H_(2)(g)+I_(2)(g)hArr 2HI(g) is 50. The equilibrium constant for the reaction 2HI(g)hArr H_(2)(g)+I_(2)(g) is :

The differential rate law for the reaction H_2 + I_2 rarr 2HI is

If the equilibrium constant of the reaction 2HIhArr H_(2)+I_(2) is 0.25, then the equilibrium constant for the reaction, H_(2)(g)+I_(2)(g)hArr 2HI(g) would be

If the equilibrium constant of the reaction 2HIhArr H_(2)+I_(2) is 0.25, then the equilibrium constant for the reaction, H_(2)(g)+I_(2)(g)hArr 2HI(g) would be