If `alpha` is a complex number such that `alpha^(2)+alpha+1=0,` then what is `alpha^(31)` equal to ?

If alpha is a complex number such that alpha^(2)+alpha+1=0 then alpha^(31) is

If alpha is a complex number such that alpha^(2)+alpha+1=0 , then the value of alpha^(61) is

If alpha is a complex number such that alpha^(2) - alpha + 1 = 0 , then alpha^(2011) =

If alpha is a complex cube root of unity such that (alpha)^2+alpha+1 = 0 , then (alpha)^31 is

If alpha is a number satisfying the equation alpha^(2)+alpha+1=0 then alpha^(31) is equal to

If alpha is a complex constant such that alpha z^2+z+ baralpha=0 has a real root, then (a) alpha+ bar alpha=1 (b) alpha+ bar alpha=0 (c) alpha+ bar alpha=-1 (d)the absolute value of the real root is 1

If alpha is a complex constant such that alpha z^2+z+ baralpha=0 has a real root, then (a) alpha+ bar alpha=1 (b) alpha+ bar alpha=0 (c) alpha+ bar alpha=-1 (d)the absolute value of the real root is 1

If alpha is a complex constant such that alpha z^(2)+z+bar(alpha)=0 has a real root,then (a) alpha+bar(alpha)=1 (b) alpha+bar(alpha)=0( c) alpha+bar(alpha)=-1 (d)the absolute value of the real root is 1

If alpha,beta are complex number such that | alpha+beta|^(2)=| alpha|^(2)+| beta|^(2)+2k then k=