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दिखाइए कि परिवलयो y^(2)=4ax तथा x^(2)=4a...

दिखाइए कि परिवलयो `y^(2)=4ax` तथा `x^(2)=4ay` के बीच क्षेत्रफल `16/3a^(2)` होगा।

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The area of the region bounded by y^(2) =4ax and x^(2) = 4ay , a gt 0 in sq. unit, is : a) 16(a^(2))/(3) b) 14 (a^(2))/(3) c) 13 (a^(2))/(3) d) 16 a^(2)

Find the area between the curves y^(2) = 4ax and x^(2)=4ay .

Which of the following pair(s) of curves is/are ortogonal? (a) y^(2)=4ax,y=e^(-x//2a) (b) y^(2)=4ax,x^(2)=4ay at (0,0) (c) xy=a^(2),x^(2)-y^(2)=b^(2) (d) y=ax,x^(2)+y^(2)=c^(2)

If the area bounded by y^(2)=4ax and x^(2)=4ay is (64)/(3) square units, then the positive value of a is

If the area bounded by y^(2)=4ax and x^(2)=4ay is (64)/(3) square units, then the positive value of a is

एक रेखा ऐसी है कि लाइनों 5 x − y + 4 = 0 तथा 3 x + 4 y − 4 = 0 के बीच इसका खंड बिंदु (1,5) पर विभाजित है (1,5)। इसके समीकरण प्राप्त करें।

एक रेखा ऐसी है कि लाइनों 5 x − y + 4 = 0 तथा 3 x + 4 y − 4 = 0 के बीच इसका खंड बिंदु (1,5) पर विभाजित है (1,5)। इसके समीकरण प्राप्त करें।

A : The area of the region bounded by y^(2)=4x,x^(2)=4y is 16//3 R: The area of the region bounded by y^(2)=4ax,x^(2)=4by is 16ab//3

The angle between the curves : y^(2)=4ax and ay=2x^(2) is :