`4000 overset(0)(A)` photons is used to break the iodine molecule, then the % of energy converted to the K.E of iodine atoms if bond dissociation energy of `I_(2)` molecule is `246.5 kJ//mol`

A photon of 4000 A^o is used to break the iodine molecule, then the % of energy converted to the K.E. of iodine atoms if bond dissociation energy of I_2 ​ molecule is 246.5 kJ/mol is:

A photon of 3000 A^o is used to break the iodine molecule, then the % of energy converted to the K.E. of iodine atoms if bond dissociation energy of I_2 ​ molecule is 255.5 kJ/mol is:

A photon of 5000 A^o is used to break the iodine molecule, then the % of energy converted to the K.E. of iodine atoms if bond dissociation energy of I_2 ​ molecule is 155.5 kJ/mol is:

A photon with a wavelength of 4000A^@ is used to break the iodine molecule, then the % of energy converted to the K.E. of iodine atoms if bond dissociation energy of I_2 molecule is 246.5 kJ/mol

The bond dissociation energy between H-O in H2O molecule (in KJ/mol)

The bond dissociation energy between Cl-Cl in Cl_2 molecule is (in KJ mol^(-1) )

Photon having wavelength 310 nm is used to break the bond of A_(2) molecule having bond energy 288 kJ mol^(-1) then % of energy of photon converted to the KE is : [hc = 12400 eV"Å" , 1 e V = 96 kJ/mol]

Bond energy of hydrogen gas is -433 kJ. How much is the bond dissociation energy of 0.5 mole of hydrogen gas?

lodine molecule dissociates into atoms after absorbing light of 4500Å . If one quantum of radiation is absorbed by each molecule, calculate the kinetic energy of iodine atoms. Bond energy of I_(2) is 240kJmol^(-1)