5 digit number divisible by 9 are to be formed by using the digits `0, 1, 2, 3, 4, 7, 8` without repetition. The total number of such 5 digited numbers formed is :

A five digit number divisible by 3 is to be formed using the digits 0,1,3,5,7,9 without repetitions. The total number of ways this can be done is

A three-digit number is to be formed using the digits 0, 1, 2, 3, 4, and 5, without repetition.

A three-digit number is to be formed using the digits 0, 1, 2, 3, 4, and 5, without repetition.

How many 5 -digit numbers divisible by 2 can be formed using digits 0,1,2,3,4,5 without repetition of digits.

Statement-1: A 5-digit number divisible by 3 is to be formed using the digits 0,1,2,3,4,5 without repetition, then the total number of ways this can be done is 216. Statement-2: A number is divisible by 3, if sum of its digits is divisible by 3.

Statement-1: A 5-digit number divisible by 3 is to be formed using the digits 0,1,2,3,4,5 without repetition, then the total number of ways this can be done is 216. Statement-2: A number is divisible by 3, if sum of its digits is divisible by 3.