Solve the equation:`sqrt(2)x^2+x+sqrt(2)=0`

Explanation

We know that in the quadratic equation ` ax^2+bx+c=0 `, the roots are given by

`x=(−b±sqrt(b^2−4ac))/(2a)`

​​For `√2x^2+x+√2=0`

`=>b^2−4ac=(1)^2−4(2)(2)=−7`

Thus, the roots are

`=>x=​(−1±sqrt(−7))/(2sqrt(2))`

​​`=>x=​(−1±sqrt(7)i)/(2sqrt(2))`

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