Let `U_n =(n!)/((n+2)!)` where `n in N`. If `S_n=sum_(n=1)^n U_n`, then `lim_(n->oo) S_n`, equals

Let U_(n)=(n!)/((n+2)!) where n in N. If S_(n)=sum_(n=1)^(n)U_(n), then lim_(n rarr oo)S_(n), equals

Consider the sequence u_n=sum_(r=1)^n r/2^r , n >= 1 then the limit_(n->oo) u_n

In a geometric series, the first term is a and common ratio is rdot If S_n denotes the sum of the terms and U_n=sum_(n=1)^n S_n ,then r S_n+(1-r)U_n equals (a) 0 b. n c. n a d. n a r

In a geometric series, the first term is a and common ratio is rdot If S_n denotes the sum of the terms and U_n=sum_(n=1)^n S_n ,then r S_n+(1-r)U_n equals a. 0 b. n c. n a d. n a r

In a geometric series,the first term is a and common ratio is r. If S_(n) denotes the sum of the terms and U_(n)=sum_(n=1)^(n)S_(n), then rS_(n)+(1+=-r)U_(n) equals 0 b.n c.na d.nar

In a geometric series , the first term is a and common ratio is r. If S_n denotes the sum of the n terms and U_n=Sigma_(n=1)^(n) S_n , then rS_n+(1-r)U_n equals

In a geometric series , the first term is a and common ratio is r. If S_n denotes the sum of the n terms and U_n=Sigma_(n=1)^(n) S_n , then rS_n+(1-r)U_n equals