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Evaluate: int(cos2x-cos2theta)/(cosx-cos...

Evaluate: `int(cos2x-cos2theta)/(cosx-costheta)dx`

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To evaluate the integral \[ \int \frac{\cos 2x - \cos 2\theta}{\cos x - \cos \theta} \, dx, \] we will follow these steps: ...
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Knowledge Check

  • int(cos 2x - cos 2 theta)/(cos x - cos theta)dx is equal to

    A
    `2(sin x + x cos theta) + C`
    B
    `2(sin x - x cos theta) + C`
    C
    `2 (sin x + 2 x cos theta) + C`
    D
    `2(sin x - 2 x cos theta) + C`

  • int(costheta-cos2theta)/(1-cos theta)d theta=

    A
    `theta+2sin theta+c`
    B
    `theta-2sin theta+c`
    C
    `2theta+2sin theta+c`
    D
    `2theta-2sin theta+c`

  • int (cosx-cos2x)/(1-cosx) dx

    A
    ` 2 sin x + x + C`
    B
    ` 2 sin x - x + C`
    C
    ` cos x + x + C`
    D
    ` 2 cos x + x + C`

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