Two radioactive materials A & B have decay constant `3lamda` and `2lamda` respectively. At `t=0` the numbers of nuclei of A and B are `4N_(0)` and `2N_(0)` respectively then,

Two radioactive materials A and B have decay constants 10lambda and lambda , respectively. If initially they have the same number of nuclei, then the ratio of the number of nuclei of A of that of B will be 1//e after a time :

Nucleus A decays into B with a decay constant lamda_(1) and B further decays into C with a decay constant lamda_(2) . Initially, at t = 0, the number of nuclei of A and B were 3N_(0) and N_(0) respectively. If at t = t_(0) number of nuclei of B becomes constant and equal to 2N_(0) , then

Nucleus A decays into B with a decay constant lamda_(1) and B further decays into C with a decay constant lamda_(2) . Initially, at t = 0, the number of nuclei of A and B were 3N_(0) and N_(0) respectively. If at t = t_(0) number of nuclei of B becomes constant and equal to 2N_(0) , then

Two radioactive substances A and B have decay constants 5lamda and lamda respectively. At t-0, they have the same number of nuclei. The ratio of number of nuclei of A to that of B will be (1//e)^(2) after a time interval of

Two radioactive materials X_(1) and X_(2) have decay constants 10 lamda and lamda respectively. If initially they have the same number of nuclei, if the ratio of the number of nuclei of X_(1) to that of X_(2) will be 1//e after a time n/(9lamda) . Find the value of n ?

Two radioactive materials X_(1) and X_(2) have decay constants 10 lamda and lamda respectively. If initially they have the same number of nuclei, if the ratio of the number of nuclei of X_(1) to that of X_(2) will be 1//e after a time n/(9lamda) . Find the value of n ?