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If y=(1+x)^(2y)+cos^2(sin^(-1)x) be a cu...

If `y=(1+x)^(2y)+cos^2(sin^(-1)x)` be a curve then find equation of normal at `x=0`.

A

`x+4y=8`

B

`x+4y=2`

C

`2x+y=2`

D

`2x-y=2`

Text Solution

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The correct Answer is:
A
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