`sucrose overset(hydrolysis)rarr A+B overset(seliwanoff)underset(reagent)rarr`
which color is obtained after above reaction?

Options

A. Red
B. Violet
C. Blue
D. Black

Answer

To solve the question regarding the color obtained after the hydrolysis of sucrose followed by the reaction with Seliwanoff's reagent, we can break it down into the following steps:

### Step 1: Hydrolysis of Sucrose
- Sucrose is a disaccharide composed of glucose and fructose. When sucrose undergoes hydrolysis, it breaks down into these two monosaccharides.
- **Reaction:**
\[ \text{sucrose} \xrightarrow{\text{hydrolysis}} \text{glucose (A)} + \text{fructose (B)} \]

### Step 2: Identification of Sugars
- Glucose is an aldose sugar (contains an aldehyde group), while fructose is a ketose sugar (contains a ketone group).
- This distinction is important because Seliwanoff's reagent is used to differentiate between aldose and ketose sugars.

### Step 3: Reaction with Seliwanoff's Reagent
- Seliwanoff's reagent consists of concentrated hydrochloric acid (HCl) and resorcinol. When this reagent is added to a solution containing sugars, it reacts differently with aldoses and ketoses.
- **Observation:**
- If a ketose sugar (like fructose) is present, the solution will turn cherry red.
- If only an aldose sugar (like glucose) is present, the solution will turn faint pink.

### Step 4: Conclusion
- Since the hydrolysis of sucrose yields both glucose and fructose, the presence of fructose (a ketose) will dominate the reaction with Seliwanoff's reagent.
- Therefore, the color obtained after the reaction will be cherry red.

### Final Answer:
The color obtained after the reaction is **cherry red**.

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