Home
Class 11
PHYSICS
A solid body rotates about a stationary ...

A solid body rotates about a stationary axis so that the rotation angle `theta` varies with time as `theta=6t-2t^(3)` radian. Find
(a) the angular acceleration at the moment when the body stops and
(b) the average value of angular velocity and angular acceleration averaged over the time interval between `t=0` and the complete stop.

Promotional Banner

Similar Questions

Explore conceptually related problems

A wheel rotates around a stationary axis so that the rotation angle theta varies with time as theta=2t^(2) radian. Find the total acceleration of the point A at the rim at the moment t=0.5 s If the radius of wheel is 1 m .

A solid body rotates about a stationary axis accordig to the law theta=6t-2t^(3) . Here theta , is in radian and t in seconds. Find (a). The mean values of thhe angular velocity and angular acceleration averaged over the time interval between t=0 and the complete stop. (b). The angular acceleration at the moment when the body stops. Hint: if y=y(t) . then mean/average value of y between t_(1) and t_(2) is ltygt=(int_(t_(1))^(t_(2))y(t)dt))/(t_(2)-t_(1))

A solid body rotates about a stationary axis accordig to the law theta=6t-2t^(3) . Here theta , is in radian and t in seconds. Find (a). The mean values of thhe angular velocity and angular acceleration averaged over the time interval between t=0 and the complete stop. (b). The angular acceleration at the moment when the body stops. Hint: if y=y(t) . then mean/average value of y between t_(1) and t_(2) is ltygt=(int_(t_(1))^(t_(2))y(t)dt))/(t_(2)-t_(1))

Angular displacement ( theta ) of a flywheel varies with time as theta=2t+3t^2 radian. The angular acceleration at t=2s is given by

Angular displacement ( theta ) of a flywheel varies with time as theta=2t+3t^2 radian. The angular acceleration at t=2s is given by

A wheel rotates around a stationary axis so that the rotation angle theta varies with time as theta=at^(2) where a=0.2rad//s^(2) . Find the magnitude of net acceleration of the point A at the rim at the moment t=2.5s if the linear velocity of the point A at this moment is v=0.65m//s .

A wheel rotates around a stationary axis so that the rotation angle theta varies with time as theta=at^(2) where a=0.2rad//s^(2) . Find the magnitude of net acceleration of the point A at the rim at the moment t=2.5s if the linear velocity of the point A at this moment is v=0.65m//s .

The angular displacement of a body is given by theta = 2t^(2) + 5t -3 . Find the value of the angular velocity and angular acceleration when t = 2s.

A solid body rotates with angular velocity vecomega=3thati+2t^(2) hatj rad//s . Find (a) the magnitude of angular velocity and angular acceleration at time t=1 s and (b) the angle between the vectors of the angular velocity and the angular acceleration at that moment.