`int(secx)/(acosx+bsinx)dx=`

int(secx)/(secx+tanx)dx=

int(secx)/(sinx+cosx)dx=

(d)/(dx)[tan^(-1)((asinx+bcosx)/(acosx-bsinx))]=

Evaluate: int(secx)/(log(secx+tanx)dx

Evaluate the following integrals: int(dx)/((acosx+bsinx)^(2)),agt0andbgt0

The integral int (dx)/(acosx+bsinx) is of the form (1)/(r )ln[tan((x+alpha)/(2))] What is r equal to ?

The integral int (dx)/(acosx+bsinx) is of the form (1)/(r )ln[tan((x+alpha)/(2))] What is alpha equal to ?

int(secx)/(log(secx+tanx))dx=

Compute the following integrals: int(secx)/(log(secx+tanx))dx

Evaluate int(secx)/(secx+tanx)dx .