[(a^(2))/(x)-(b^(2))/(y),=0],[(a^(2)b)/(x)+(b^(2)a)/(y),=a+b," Where "x,y]

Solve the following pair of equations for x and y : (a^(2))/(x)-(b^(2))/(y)=0, (a^(2)b)/(x)+(b^(2)a)/(y)=a+b , x ne 0 , y ne 0 .

(a)/(x)-(b)/(y)=0,(ab^(2))/(x)+(a^(2)b)/(y)=a^(2)+b^(2)

Solution to (a^2)/(x)-(b^2)/(y)=0, (a^2b)/(x)+(b^2a)/(y)=a+b,x ne0,y ne0 is………

Solve the following system of equations in x and y:(a)/(x)-(b)/(y)=0,quad (ab^(2))/(x)+(a^(2)b)/(y)=a^(2)+b^(2) where x,y!=0

Solve : {:((a)/(x)-(b)/(y)=0),((ab^(2))/(x)+(a^(2)b)/(y)=a^(2)+b^(2)):}

(x)/(a)+(y)/(b)=a^(2)+b^(2) and (x)/(a^(2))+(y)/(b^(2))=a+b

(x)/(a)+(y)/(b)=a+b(x)/(a^(2))+(y)/(b^(2))=2,a!=0,b!=0

Solve: (x)/(a)+(y)/(b)=a^(2)+b^(2) and (x)/(a^(2))+(y)/(b^(2))=a+b

Evaluate (y^(2))/(b^(2))-(x^(2))/(a^(2)) , where x= a tan theta and y = b sec theta

Solve the following system of equations in x and y : a/x-b/y=0,\ \ \ \ (a b^2)/x+(a^2b)/y=a^2+b^2 , where x ,\ y!=0 .