Solve the equation:`x^2-x+2=0`

Explanation

We know the roots of the quadratic equation `Ax^2+Bx+C=0 `are

`x=(−B±sqrt(B^2−4AC))/(2A)`

​​The given equation is
`x^2−x+2=0`

for the given equation, `B*2−4AC=(−1)^2−4(1)(2)=−7`

So the roots are

`x=(−(−1)±sqrt(−7))/(2)`

​​`x=(1±sqrt(7)​i)/2​`