Prove that, `sintheta+sin2theta+sin3theta+ . . .sinntheta=((sinntheta)/(2)"sin"(n+1)/(2)theta)/("sin"(theta)/(2))` for all `ninN`.

Prove that, sintheta+sin2theta+sin3theta+ . . .sinntheta=(sin""(ntheta)/(2)"sin"(n+1)/(2)theta)/("sin"(theta)/(2)) for all ninN .

Prove that , sin theta + sin 2theta + ……+ sin n theta = ( (sin( n theta/(2)) sin ((n+1)/(2))theta))/(sin theta/2) , for all n in N .

Solve: 4sintheta sin2theta sin4theta = sin 3theta

Prove that sin theta+sin3 theta+sin5 theta+....+sin(2n-1)theta=(sin^(2)n theta)/(sin theta)

Prove that sintheta+sin3theta+sin5theta+.....+sin(2n-1)theta=(sin^2ntheta)/(sintheta)dot

Prove that sintheta+sin3theta+sin5theta+.....+sin(2n-1)theta=(sin^2ntheta)/(sintheta)dot

Prove that sintheta+sin3theta+sin5theta+.....+sin(2n-1)theta=(sin^2ntheta)/(sintheta)dot

Prove that sintheta+s in3theta+sin5theta++sin(2n-1)theta=(sin^2ntheta)/(sintheta)dot

Prove that sin^2 theta+sin^2 2theta+sin^2 3theta+....+sin^2 n theta=n/2-(sin n theta cos(n+1)theta)/(2sin theta)

Prove that sin theta+sin2 theta+sin4 theta+sin5 theta=4cos((theta)/(2))cos((3 theta)/(2))sin3 theta