`P ,Q` have position vectors ` vec a& vec b` relative to the origin `' O^(prime)&X , Ya n d vec P Q` internally and externally respectgively in the ratio `2:1` Vector ` vec X Y=` a.`3/2( vec b- vec a)` b. `4/3( vec a- vec b)` c. `5/6( vec b- vec a)` d. `4/3( vec b- vec a)`

P ,Q have position vectors vec a& vec b relative to the origin ' O^(prime)&X , Ya n d vec P Q internally and externally respectgively in the ratio 2:1 Vector vec X Y=

P ,Q have position vectors vec a& vec b relative to the origin ' O^(prime)&X , Ya n d vec P Q internally and externally respectgively in the ratio 2:1 Vector vec X Y= 3/2( vec b- vec a) b. 4/3( vec a- vec b) c. 5/6( vec b- vec a) d. 4/3( vec b- vec a)

P ,Q have position vectors vec a& vec b relative to the origin ' O^(prime)&X , Ya n d vec P Q internally and externally respectgively in the ratio 2:1 Vector vec X Y= 3/2( vec b- vec a) b. 4/3( vec a- vec b) c. 5/6( vec b- vec a) d. 4/3( vec b- vec a)

P ,Q have position vectors vec a& vec b relative to the origin ' O^(prime)&X , Ya n d vec P Q internally and externally respectgively in the ratio 2:1 Vector vec X Y= 3/2( vec b- vec a) b. 4/3( vec a- vec b) c. 5/6( vec b- vec a) d. 4/3( vec b- vec a)

If vec a_|_ vec b , then vector vec v in terms of vec aa n d vec b satisfying the equation s vec v . vec a=0a n d vec v . vec b=1a n d[ vec v vec a vec b]=1 is a. vec b/(| vec b|^2)+( vec axx vec b)/(| vec axx vec b|^2) b. vec b/(| vec b|^2)+( vec axx vec b)/(| vec axx vec b|^2) c. vec b/(| vec b|^2)+( vec axx vec b)/(| vec axx vec b|^2) d. none of these

If vec p = vec a + vec b, vec q = vec a-vec b | vec a | = | vec b | = 1 then | vec p xxvec q | =

If vec a_|_ vec b , then vector vec v in terms of vec aa n d vec b satisfying the equation s vec vdot vec a=0a n d vec vdot vec b=1a n d[ vec v vec a vec b]=1 is vec b/(| vec b|^2)+( vec axx vec b)/(| vec axx vec b|^2) b. vec b/(| vec b|^)+( vec axx vec b)/(| vec axx vec b|^2) c. vec b/(| vec b|^2)+( vec axx vec b)/(| vec axx vec b|^) d. none of these

If vec a_|_ vec b , then vector vec v in terms of vec aa n d vec b satisfying the equation s vec vdot vec a=0a n d vec vdot vec b=1a n d[ vec v vec a vec b]=1 is vec b/(| vec b|^2)+( vec axx vec b)/(| vec axx vec b|^2) b. vec b/(| vec b|^)+( vec axx vec b)/(| vec axx vec b|^2) c. vec b/(| vec b|^2)+( vec axx vec b)/(| vec axx vec b|^) d. none of these

If vec a and vec b are two vectors such that | vec a|=2, |vecb|=3 and ( vec a . vec b )=4 then \ f i n d |( vec a - vec b )|

Show that the points with position vectors vec a-2vec b+3vec c,-2vec a+3vec b-vec c and 4vec a-7vec b+7vec c are collinear.