" (vi) "(tan(A+B))/(cot(A-B))=(tan^(2)A-tan^(2)B)/(1-tan^(2)A tan^(2)B)

Prove that: (tan(A+B))/(cot(A-B))=(tan^(2)A-tan^(2)B)/(1-tan^(2)A tan^(2)B)

Prove that: ("tan"(A+B))/("cot"(A-B))=\ (tan^2A-tan^2B)/(1-tan^2Atan^2B)

Prove that: tan(A+B)tan(A-B)=(tan^(2)A-tan^(2)B)/(1-tan^(2)A tan^(2)B)

Prove that tan(A+B)/cot(A-B)=(tan^2A-tan^2B)/(1-tan^2Atan^2B)

if A-B=(pi)/(4) and A+B=(pi)/(3) then (tan^(2)A-tan^(2)B)/(1-tan^(2)A tan^(2)B)

If A,B,C,D are the angles of a quadrilateral, then (tan A+tan B+tan C+tan D)/(cot A+cot B+cot C+cot D) is equal to: (a) tan A tan B tan C tan D(b)tan^(2)A+tan^(2)B+tan^(2)C+tan^(2)D(d)sum tan A tan B tan C

Prove: tan^(2)A sec^(2)B-sec^(2)A tan^(2)B=tan^(2)A-tan^(2)B

(b-c)/(a) = (tan B/2-tan( c/2))/(tan B/2+tan C/2)

If A and B are acute angles such that tan A=(1)/(2),tan B=(1)/(3) and tan(A+B)=(tan A+tan B)/(1-tan A tan B), find A+B

In any Delta ABC, prove that : ((a-b)/(c))=(tan((A)/(2))-tan((B)/(2)))/(tan((A)/(2))+tan((B)/(2)))