if `f(x)=x^2-ax+3 , x` is rational and `f(x)=2-x , x` is irrational is continuous at exactly two points, then the possible values of `a `

f(x)=1 for x is rational f(x)=-1 for x irrational, f is continuous on

f(x)=1 for x is rational -1 for x is irrational,f is continuous on

If f(x)={x^(2) if x is rational and 0, if x is irrational }, then

A function f(x) is defind as f(x)={{:(x^(2)+ax+1, " x is rational "),(ax^(2)+2x+b,"x is irrational "):} is continuous at x=1and 3 , them find the values of a and b.

Let f(x)=x^2 if x is rational and f(x)=1-x^2 if x is irrational then the number of points of continuity of f is

Find the value of x where f(x)={x ,if x is rational 1-x ,if x is irrational is continuous dot

If f(x)={x ,x is rational 1-x ,x is irrational ,then f(f(x)) is

If f(x)={x ,x is rational 1-x ,x is irrational ,then f(f(x)) is

If f(x)={x ,x is rational 1-x ,x is irrational ,then f(f(x)) is