40 miligram diatomic volatile substance `(X_2)` is converted to vapour that displaced `4.92mL` of air at 1atm and 300k. Atomic mass of element X is nearly :

40 mg of gaseous substance ( X_(2) ) occupies 4.8 mL of volume at 1 atm and 27^(@) C. Atomic mass of element X is : (R:0.08 atm L/mole- k )

Vapour density of a volatile substance is 4 (O_(2)= 1). Its molecular weight would be

In Victor Meyer's experiment, 0.6 g of a volatile substance displaced 112 mL of air at S.T.P. Find the molecular mass of the substance.

In Victor Meyers method, 0.2 g of an organic substance displaced 56 mL of air at STP.The molecular mass of the compound is

In Victor Meyers method, 0.2 g of an organic substance displaced 56 mL of air at STP.The molecular mass of the compound is

In a Victor Meyer's determination of molecular mass, 0.15 g of a volatile substance displaced 31.64 mL of air at 25°C and 755 mm pressure. Calculate the molecular mass of the substance.

The density of vapours of a particualr volatile diatomic species A_(2) was found to be 10 milligram/ml at 1 atm and 273 K. Its atomic weight is given by : [Assume ideal gas behaviour]

1 mole of a diatomic element X_2 contains 34 and 40 moles of electrons and neutrons respectively. The isotopic formula of the element is: