sqrt(x^(2)+4x+6)

int(dx)/(sqrt(2x^(2)+4x+6))

If f(x)=sqrt(x^(2)-4x+4)+6sqrt(x^(2)) is minimum then the number of values of x is:

If I=int(dx)/(x-sqrt(9x^(2)+4x+6)) to evaluate I,one of the most proper substitution could be

The number of real solutions of sqrt(x^(2)-4x+3)+sqrt(x^(2)-9)=sqrt(4x^(2)-14x+6)

Solve sqrt(x^(2)+4x-21)+sqrt(x^(2)-x-6)=sqrt(6x^(2)-5x-39)

Solve the following: (sqrt(x^(2)-5x+6)+sqrt(x^(2)-5x+4))^((x)/(2))+(sqrt(x^(2)-5x+6)-sqrt(x^(2)-5x+4))^(x/2)=2^((x+4)/(4))

f(x)=(sqrt(x^(2)+x-6))/(x^(2)-4)

Integrate the function sqrt(x^2+4 x+6) d x

If I=int(((2x-1)cos(sqrt(4x^2-4x+6)))/sqrt(4x^2-4x+6))dx