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" (c) "50b^(2)c^(2)-98a^(2)...

" (c) "50b^(2)c^(2)-98a^(2)

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If 8a^(2)+50b^(2)+98c^(2)-20ab-70bc-28ac=0 then show that 2a=5b=7c

Simplify: (a^(2)-(b-c)^(2))/((a+c)^(2)-b^(2))+(b^(2)-(a-c)^(2))/((a+b)^(2)-c^(2))+(c^(2)-(a-b)^(2))/((b+c)^(2)-a^(2))

Prove that 2b^(2)c^(2) +2c^(2)a^(2) +2a^(2)b^(2) -a^(4)-b^(4)-c^(4)= (a+b+c) (b+c-a) (c+a-b) (a+b-c)

Factorise : (a^(2)-b^(2))(a+b)+(b^(2)-c^(2))(b+c)+(c^(2)-a^(2))(c+a)

If a,b,c are in H.P., then (c^(2)(b-a)^(2)+a^(2)(c-b)^(2))/(b^(2)(a-c)^(2)) =

If a+b=z, c+a=y, b+c=x, x^(2)+y^(2)+z^(2)=50 and xy+yz+zx=47 then find the value of a^(2)+b^(2)+c^(2)+ab+bc+ca .

Prove that |{:((b+c)^(2), a^(2), bc),((c+a)^(2), b^(2), ca),((a+b)^(2), c^(2), ab):}|= (a-b) (b-c)(c-a)(a + b+c) (a^(2) + b^(2) + c^(2)) .

(a^(2)-b^(2)-2bc-c^(2))/(a^(2)+b^(2)+2ab-c^(2)) is equivalent to (a-b+c)/(a+b+c)( b) (a-b-c)/(a-b+c)(c)(a-b-c)/(a+b-c)(d)(a+b+c)/(a-b+c)

(50a^(2)-98b^(2))/(10a-14b)