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Three distinct lines (x-1)/3=(y-2)/2=(z-...

Three distinct lines `(x-1)/3=(y-2)/2=(z-3)/1, (x-1)/5=(2y-4)/3=(3z-9)/1, (x-lambda^2)/3=(y-2)/2=(z-3)/lambda` are concurrent, then value of `lambda` may be...

Text Solution

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let
`L_1 -> (x-1)/3 = (y-2)/2 = (z-3)/1 = k`
x=3k+1 y=2k+2 z=k+3 -(1)
let
`L_2 -> (x-1)/5 = (2y-4)/3 = (3z-9)/1 = l`
x=5l+1 y=`(3l+4)/2` z=`(9+l)/3` -(2)
let
`L_3 -> (x-lambda^2)/3 = (y-2)/2 = (z-3)/lambda = m`
...
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