Find the length of the tangent for the curve `y=x^3+3x^2+4x-1` at point `x=0.`

Find the length of tangent to the curve y=4x^3-2x^5 at (-1,1)

find the slope of the tangent to the curve y = x^3 - 3x+2 at the point whose x-coordinate is 2.

Find the slope of the tangent to the curve, y=x^(3)-3x+2 at the point whose x co-ordinate is 3.

Find the slope of the tangent to the curve y = x^(3) - 3x + 2 at the point whose x-coordinate is 3.

Find the slope of the tangent to the curve y = x^(3) –3x + 2 at the point whose x-coordinate is 3.

Find the slope of the tangent to the curve y = x^(3) –3x + 2 at the point whose x-coordinate is 3.

Find the slope of the tangent to the curve y = x^(3) –3x + 2 at the point whose x-coordinate is 3.

Find the slope of the tangent to the curve y =3x^2-4x at the point, whose x-co-ordinats is 2.

Find the slope of the tangent to the curve y=3x^(2)-4x at the point, whose x - co - ordinate is 2.

Find the equation of the tangent line to the curve y=(3x^2-1)/x at the point (1,2) is (a) 4x-y-1=0 (b) 4x+y+2=0 (c)x-y-1=0 (d) 4x-y-2=0