Horizontal component of earth at a place is `3*2xx10^-5T`, and angle of dip is `60^@`. The resultant intensity of earth's field at the place is

Calculate the horizontal component of earth's magnetic field at place, where angle of dip is 30^@ . Given vertical component of earth's field at the place is 0*12sqrt3xx10^-4T .

At a certain place the horizontal component of the earth's magnetic field is B_(0) and the angle of dip is 45^(@) . The total intensity of the field at that place will be

At a certain place the horizontal component of the earth's magnetic field is B_(0) and the angle of dip is 45^(@) . The toyal intensity of the field at that place will be

The horizontal component of earths's magnetic field at a place is 0.3 xx 10^-4T . If the angle of dip is 60^@ , what is the total earth's magnetic field?

At a given place on earth's surface the horizontal component of earths magnetic field is 2xx10^(-5)T and resultant magnetic field is 4xx10^(-5)T . The angles of dip at this place is

At a given place on earth's surface the horizontal component of earths magnetic field is 2xx10^(-5)T and resultant magnetic field is 4xx10^(-5)T . The angles of dip at this place is

The horizontal component of earth's magnetic field at a place is 3.6 xx 10^(-5) T. if the angle of dip at this place is 60^(@) , the vertical components of earth's field at this place is