Home
Class 12
CHEMISTRY
In isotonic solution of protein A and pr...

In isotonic solution of protein A and protein B, 0.73g of protein A is dissolved in 250ml of solution while 1.65g of protein B is dissolved in 1L solutionthen what is ratio of molecular mass of protein A and protein B?

Text Solution

AI Generated Solution

The correct Answer is:
To find the ratio of the molecular mass of protein A (MA) to protein B (MB) in isotonic solutions, we can follow these steps: ### Step 1: Understand the concept of isotonic solutions In isotonic solutions, the osmotic pressure of both solutions is equal. The formula for osmotic pressure (π) is given by: \[ \pi = iCRT \] where: - \(i\) = van 't Hoff factor (which is 1 for proteins), - \(C\) = concentration (in molarity), - \(R\) = gas constant, - \(T\) = temperature (in Kelvin). ### Step 2: Set up the equation for both proteins Since the osmotic pressures are equal for both proteins, we can write: \[ \pi_A = \pi_B \] This leads to: \[ C_A = C_B \] ### Step 3: Calculate the concentrations of both proteins The concentration \(C\) is defined as the number of moles of solute per liter of solution: \[ C = \frac{\text{number of moles}}{\text{volume in liters}} \] The number of moles can be calculated as: \[ \text{number of moles} = \frac{\text{mass (g)}}{\text{molecular mass (g/mol)}} \] #### For protein A: - Mass = 0.73 g - Volume = 250 mL = 0.250 L The concentration \(C_A\) can be expressed as: \[ C_A = \frac{0.73 / M_A}{0.250} \] #### For protein B: - Mass = 1.65 g - Volume = 1 L The concentration \(C_B\) can be expressed as: \[ C_B = \frac{1.65 / M_B}{1} \] ### Step 4: Set the concentrations equal Since \(C_A = C_B\), we can set up the equation: \[ \frac{0.73 / M_A}{0.250} = \frac{1.65 / M_B}{1} \] ### Step 5: Cross-multiply to solve for the ratio of molecular masses Cross-multiplying gives: \[ 0.73 \cdot M_B = 1.65 \cdot (0.250 \cdot M_A) \] This simplifies to: \[ 0.73 \cdot M_B = 0.4125 \cdot M_A \] ### Step 6: Rearranging to find the ratio Rearranging gives: \[ \frac{M_A}{M_B} = \frac{0.73}{0.4125} \] ### Step 7: Calculate the ratio Now, calculate the ratio: \[ \frac{M_A}{M_B} = \frac{0.73}{0.4125} \approx 1.77 \] ### Final Answer The ratio of the molecular mass of protein A to protein B is: \[ \frac{M_A}{M_B} \approx 1.77 \] ---
Promotional Banner

Similar Questions

Explore conceptually related problems

If 250 cm^3 of an aqueous solution containing 0.73 g of a protein A of isotonic with one litre of another aqueous solution containing 1.65 g of a protein B, at 298 K, the ratio of the molecular masses of A and B is ________ xx 10^(-2) ( to the nearest integer).

A purified cytochrome protein was found to contain 0.376 % iron. What is the minimum molecular mass of the protein?

Osomotic pressure of a solution containing 2 g dissolved protein per 300 cm^3 of solution is 20 mm of Hg at 27^@C . The molecular mass of protein is

200 mL of a very dilute aqueous solution of a protein contains 1.9 gm of the protein . If osmotic rise of such a solution at 300K is found to be 38 mm of solution then calculate molar mass of the protein . (Take R = 0.008 L atm mol^(-1) K^(-1) )

4.5g mass of a substance (molar mass = 90g/mol) is dissolved in 250ml solution, the molarity of solution is

A solution containing 3 g of solute A (M=60 g/mol) in 1L solution is isotonic with a solution containing 8.55 g of solute B in 500 mL solution. What is the molar mass of B?

Calculate the molarity of the following solution: (a) 4g of caustic soda is dissolved in 200mL of the solution. (b) 5.3 g of anhydrous sodium carbonate is dissolved in100 mL of solution. (c ) 0.365 g of pure HCl gas is dissolved in 50 mL of solution.