If `alpha+beta+gamma=0`, `sin2alpha+sin2beta+sin2gamma=lambdasinalphasinbetasingamma`. Find `lambda`.

If alpha+beta+gamma=0sin2 alpha+sin2 beta+sin2 gamma=lambda sin alpha sin beta sin gamma Find lambda.

If alpha+beta-gamma=pi , then sin^2alpha+sin^2beta-sin^2gamma=

If alpha+beta-gamma=pi and sin^2alpha+sin^2beta-sin^2gamma=lambda sinalpha sinbeta cosgamma, then write the value of lambda

If alpha+beta-gamma=pi, and sin^(2)alpha+sin^(2)beta-sin^(2)gamma=lambda s in alpha s in beta cos gamma then write the value of lambda

Given alpha+beta-gamma=pi and sin^(2)alpha+sin^(2)beta-sin^(2)gamma=lambdasin alphasin beta cos gamma then find the value of lambda

sin 2 alpha + sin 2 beta + sin 2 gamma - sin2(alpha + beta + gamma )=

If cos alpha+cos beta+cos gamma=0=sin alpha+sin beta+sin gamma , then (sin3alpha+sin3beta+sin3gamma)/(sin(alpha+beta+gamma)) is equal to

If cos alpha+cos beta+cos gamma=0=sin alpha+sin beta+sin gamma , then (sin3alpha+sin3beta+sin3gamma)/(sin(alpha+beta+gamma)) is equal to

If cos alpha+cos beta+cos gamma=0=sin alpha+sin beta+sin gamma , then (sin3alpha+sin3beta+sin3gamma)/(sin(alpha+beta+gamma)) is equal to