If `cos theta=(a cosphi+b)/(a+bcosphi)` then `tan(theta/2)/tan(phi/2)=` (A) `(a-b)/(a+b)` (B) `(a+b)/(a-b)` (C) `sqrt((a+b)/(a-b))` (D) `sqrt((a-b)/(a+b))`

If cos theta =(a cos phi+b)/(a+bcosphi) then ("tan"(theta)/2)/("tan"(phi)/2)=

If cos theta=(a cos phi+b)/(a+b cos phi) then tan^(2)((theta)/(2)) is equal to

If cos theta = (a cos phi + b) / (a + b cos phi) then (tan ((theta) / (2))) / (tan ((phi) / (2))) = (A) ( ab) / (a + b) (B) (a + b) / (ab) (C) sqrt ((a + b) / (ab)) (D) sqrt ((ab) / (a + b))

If costheta=(acosphi+b)/(a+bcosphi) . Show that : tan.(theta)/(2)=pmsqrt((a-b)/(a+b))tan.(phi)/(2).

If costheta=((acosphi+b))/((a+bcosphi)) , then the value of tan (theta//2) is equal to

If sintheta+sinphi=aandcostheta+cosphi=b , then tan((theta-phi)/(2))=?

If cos theta=(acosphi+b)/(a+bcosphi)(theta,phiacute angle) show that tan(theta/2)=sqrt((a-b)/(a+b))tan (phi/2)(a>b)

If tan theta=(b)/(a) then a cos 2 theta+b sin 2 theta=

If tan theta=a/b then b cos 2theta+asin 2theta=