The speed of a train increases at a constant rate `alpha` from zero to v and then remains constant for an interval and finally decreases to zero at a constant rate `beta`. The total distance travelled by the train is l. The time taken to complete the journey is t. Then,

The speed of a train increases at a consant rate alpha from zero to v and then remains constant for an interval and finally decreases to zero at a constant rate beta . If l be the total distance described, and the total time then

the velcoity of a trian incrreases at a constant rate alpha from 0 to v and then remains constant for same interval and then finally decreases to zero at constant rate beta .if the total distance coverd by the the particle x,then show that the total time taken will be tx/v+v/2[1/alpha + 1/beta] .

A train accelerates from rest at a constant rate alpha for some time and then it retards to rest at the constant rate beta . If the total distance covered by the train is s, then the velocity of the train is

A bus starting from rest, accelerates at the rate of f through a distance S, then continues at constant speed for time t and declerates at the rate f/2 to come to rest. If the total distance travelled is 15 S then S =

A car starting from rest, accelerates at the rate of f through a distance S, then continues at constant speed for time t and declerates at the rate f/2 to come to rest. If the total distance travelled is 15 S then S =