ABCD is a parallelogram . If `vec(AB)=vec(a), vec(BC)=vec(b)`, then what `vec(BD)` equal to ?

Let ABCD is a parallelogram. If AB= vec(a) and BC= vec(b) then what is BD equal to ?

If ABCD is a parallelogram, then vec(AC) - vec(BD) =

If ABCD is a parallelogram, then vec(AC) - vec(BD) =

If ABCD is a parallelogram and vec AB = vec a , vec BC= vec b then show that vec AC = vec a+ vec b and vec BD = vec b- vec a .

If ABCDEF is a regular hexagon with vec(AB) = vec(a) ,vec(BC ) = vec(b) then vec(CE) equals :

If ABCD is a parallelogram, then vec(AB)+vec(AD)+vec(CB)+vec(CD) is equal to

Let ABCD be a parallelogram such that vec(AB)= vec(q), vec(AD) = vec(P) and angleBAD be an acute angle. If vec(r) is the vector that coincides with the altitude directed from the vertex B to the side AD, then vec(r) is given by-

ABCDEF is a regular hexagon. If vec(AB) = vec(a) and vec(BC) = vec(b), " find " vec(CD), vec(DE), vec(EF) and vec(FA) in terms of vec(a) and vec(b)

ABCDEF is a regular hexagon. If vec(AB)=vec(a) " and " vec(BC)=vec(b), " find " vec(EF), vec(CD), vec(BF) " and " vec(BD) in terms of vec(a) " and " vec(b) .