If `a_1, a_2, a_3, ` be terms of an A.P. if `(a_1+a_2++a_p)/(a_1+a_2++a_q)=(p^2)/(q^2), p!=q ,t h e n(a_6)/(a_(21))` equals 41/11`` b. 7/2`` c. 2/7`` d. 11/41

If a_1, a_2, a_3, be terms of an A.P. and (a_1+a_2+.....+a_p)/(a_1+a_2+.....+a_q)=(p^2)/(q^2), p!=q ,t h e n(a_6)/(a_(21)) equals to (a).41/11 (b). 7/2 (c). 2/7 (d). 11/41

If a_1, a_2, a_3, be terms of an A.P. and (a_1+a_2+.....+a_p)/(a_1+a_2+.....+a_q)=(p^2)/(q^2), p!=q ,t h e n(a_6)/(a_(21)) equals to (a).41/11 (b). 7/2 (c). 2/7 (d). 11/41

Let a_1 , a_2 , a_3,.... be terms of an A.P. if (a_1 + a_2 +....+ a_p)/(a_1 + a_2 +...+ a_q) = p^2/q^2. p ne q then a_6/a_21 equals

Let a_1,a_2,a_3………. be term of an A.P. if (a_1+a_2+….+a_p)/(a_1+a_2+………+a_q)=p^2/q^2 p!=q then a_6/ a_21 euqals (A) 41/11 (B) 11/41 (C) 13/44 (D) 15/41

Let a_1,a_2,a_3,...... be an A.P. such that [a_1+a_2+......+a_p]/[a_1+a_2+a_3+......+a_q]=p^3/q^3 ; p!=q .Then a_6/a_[21] is equal to:

If a_1,a_2,a_3,...,a_(n+1) are in A.P. , then 1/(a_1a_2)+1/(a_2a_3)....+1/(a_na_(n+1)) is

Let a_1, a_2, ,a_(10) be in A.P. and h_1, h_2, h_(10) be in H.P. If a_1=h_1=2a n da_(10)=h_(10)=3,t h e na_4h_7 is

Let a_1, a_2, a_3, ...a_(n) be an AP. then: 1 / (a_1 a_n) + 1 / (a_2 a_(n-1)) + 1 /(a_3a_(n-2))+......+ 1 /(a_(n) a_1) =