Angle of intersection of two circle and orthogonal intersection of circles

Angle of intersection of two circles is given by :

Two congruent intersecting circles.

Angle OF Intersection OF two circle|| Condition OF orthogonality|| Radical axis (theory)

The pints of intersection of two equal circles which out orthogonally are (2,3) and ( 5,4) Then the radius of each circle is

radical axis,angle OF intersection,condition OF orthogonality||family OF circle

If the circles x ^(2) + y ^(2) + 5x -6y-1=0 and x ^(2) + y^(2) +ax -y +1=0 intersect orthogonally (the tangents at the point of intersection of the circles are at right angles), the value of a is

The equation of a circle C_1 is x^2+y^2= 4 . The locus of the intersection of orthogonal tangents to the circle is the curve C_2 and the locus of the intersection of perpendicular tangents to the curve C_2 is the curve C_3 , Then

The equation of a circle C_1 is x^2+y^2= 4 . The locus of the intersection of orthogonal tangents to the circle is the curve C_2 and the locus of the intersection of perpendicular tangents to the curve C_2 is the curve C_3 , Then

The equation of a circle C_(1) is x^(2)+y^(2)=4 The locus of the intersection of orthogonal tangents to the circle is the curve C_(2) and the locus of the intersection of perpendicular tangents to the curve C_(2) is the curve C_(3), Then

The equation of a circle C_1 is x^2+y^2= 4 . The locus of the intersection of orthogonal tangents to the circle is the curve C_2 and the locus of the intersection of perpendicular tangents to the curve C_2 is the curve C_3 , Then