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(16)^(1/3) + (54)^(1/3)+ (192)^(1/3) - (...

(16)^(1/3) + (54)^(1/3)+ (192)^(1/3) - (375)^(1/3)

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3(250)^((1)/(3))+7(16)^((1)/(3))-4(54)^((1)/(3))

Sum up to 16 terms of the series (1^(3))/(1) + (1^(3) + 2^(3))/(1 + 3) + (1^(3) + 2^(3) + 3^(3))/(1 + 3 + 5) + .. is

Sum up to 16 terms of the series (1^(3))/(1) + (1^(3) + 2^(3))/(1 + 3) + (1^(3) + 2^(3) + 3^(3))/(1 + 3 + 5) + .. is

{(1/3)^2}^4 is equal to (a) (1/3)^6 (b) (1/3)^8 (c) (1/3)^(24) (d) (1/3)^(16)

{(1/3)^2}^4 is equal to (1/3)^6 (b) (1/3)^8 (c) (1/3)^(24) (d) (1/3)^(16)

Factorise: (1)/(64) a ^(3) - (1)/(16) a ^(2) b + (1)/(12) ab ^(2) - (1)/(27) b ^(3)

Find ((16)^(1/3))

{(1/3)^(-3)-(1/2)^(-3)}-:(1/4)^(-3) = (19)/(64) (b) (64)/(19) (27)/(16) (d) (-19)/(64)