" (a) "2y+(5)/(2)=(37)/(2)quad " (b) "5t+28=10

.Solve the following equations: (a) 2y+(5)/(2)=(37)/(2), (b) 5t+28=10, (c)(a/5)+3=2 (d)(5/2)x=-5x^(10), (e) (5/2)x=(25/4), (g) 7m+(19/2)=13

Solve : 2y + 5/2 = 37/2

Solve equation 2y+5/2=37/2

Simplify 5t+28=10

In DeltaABC , if tan.(A)/(2)=(5)/(6),tan.(B)/(2)=(20)/(37) , then

If (tan A)/(2)=(5)/(6),(tan B)/(2)=(20)/(37). Then sides are

Simplify. (i) (x^2-5) (x+5)+25 (ii) (a^2+5) (b^3+3)+5 (iii) (t+s^2) (t^2-s) (iv) (a+b)(c-d)+(9a-b)(c+d)+2(ac+bd) (v) (x+y)(2x+y)+(x+2y)+(x+2y)(x-y) (vi) (x+y)(x^2-xy+y^2) (vii) (1.5x-4y)(1.5x+4y+3)-4.5x+12y (viii) (a+b+c)(a+b-c)

Find the values of following . (a) (tan^(2)37(1)/(7)^(@)+1)/(tan^(2)37(1)/(2)^(@)-1) (b) (3 tan^(2)5^(@)-1)/(3tan5^(@)-tan^(3)5^(@))