" 10."(sqrt(2)/5)^(8)/(sqrt(2)/5)^(13)

Simplify: (i)\ ((sqrt(2))/5)^8\ -:((sqrt(2))/5)^(13)

(iii) ((sqrt(2))/(5))^(8)-:((sqrt(2))/(5))^(1/3)

Simplify the following (sqrt2/5)^8divide(sqrt2/5)^(13)

The modulus of the complex number ((2+i sqrt(5))/(2-i sqrt(5)))^(10)+((2-i sqrt(5))/(2+i sqrt(5)))^(10) is equal to

8. (sqrt(5)-2)^(2)=?-sqrt(80)

The following are the steps involved in finding the value of x-y from (sqrt(8)-sqrt(5))/(sqrt(8)+sqrt(5))=x-ysqrt(40) . Arrange them in sequential order. (A) (13-2sqrt(40))/(8-5)=x-ysqrt(40) (B) ((sqrt(8))^(2)+(sqrt(5))^(2)-2(sqrt(8))(sqrt(5)))/((sqrt(8))^(2)-(sqrt(5))^(2))=x-ysqrt(40) (C) x-y=(11)/(3) (D) x=(13)/(3) and y=(2)/(3) (E) ((sqrt(8)-sqrt(5))(sqrt(8)-sqrt(5)))/((sqrt(8)+sqrt(5))(sqrt(8)-sqrt(5)))=x-ysqrt(40)

The value of int_5^(10)(sqrt(x+sqrt(20 x-100))+sqrt(x-sqrt(20 x-100)))dx"i s" (1) 10sqrt(5) (2) 5sqrt(5) (3) 10sqrt(2) (4) 8sqrt(2)

If sqrt(5)=2.236, then the value of (sqrt(5))/(2)-(10)/(sqrt(5))+sqrt(125) is equal to (a) 5.59(b)7.826(c)8.944 (d) 10.062

The sum of the first n terms of the series (1)/(sqrt(2)+sqrt(5))+(1)/(sqrt(5)+sqrt(8))+(1)/(sqrt(8)+sqrt(11))+ .... is

ln Delta ABC , tan A=3 , tan B=(2)/(3) c=sqrt(10) then circum radius of Delta is (1) 11sqrt((13)/(10)) (2) (10sqrt(13))/(11) (3) (sqrt(130))/(11) (4) (5sqrt(13))/(11)