[" 3.If "n" is a multiple of "6" and "alpha,beta" are the "],[" roots of "x^(2)+x+1=0" then "],[(1+alpha)^(-n)+(1+beta)^(-n)=]

Assertion (A): If n is a multiple of 6 and alpha, beta are the roots of x^(2) + x +1=0 then (1+alpha)^(-n)+ (1+beta)^(-n)=2 Reason (R) : The roots of x^(2) + x + 1= 0 are omega, omega^(2) and omega^(n), omega^(2n)= 2 when n=3k, k in z

If alpha,beta are the roots of x^(2)-2x+4=0 then alpha^(n)+beta^(n) is

If alpha and beta are the roots of x^(2)-2x +4=0 then alpha^(n) + beta^(n) is equal to

If alpha, beta are the roots of x^(2)-a x+b=0 and A_(n)='alpha'^(n)+beta^(n) , then A_(n+1)=

If alpha and beta are the roots of the equation x^(2)-ax+b=0 and A_(n)=alpha^(n)+beta^(n)

If alpha a n d beta are the roots of x^2-3x+2=0 find the value of (1+ alpha )(1+ beta ).

If alpha, beta are the roots of the equation x^2-4x+8 = 0 then for any n in N, (alpha)^(2n)+(beta)^(2n) =