A uniform magnetic field of intensity `1T` is applied in a circular region of radius `0.1 m`, directed into the plane of paper. A charged particle of mass `5xx10^(-5)kg` and charge `q=5xx10^(-4)C` enters the field with velocity `1//sqrt(3)m//s` making an angle of `phi` with a radial line of circular region in such a way that it passes through centre of applied field the angle `phi` is

A uniform magnetic field is applied in a circular region of radius R as shown in the given figure. A charged particle of charge q and mass m enters with a velocity from point P along the line that is making an angle with the line segment OP, in the region of magnetic field. The charged particle is found to pass through the centre of the circular region. Find the angle theta . Given : B = 1 T, R = 10 cm, m = 6 xx 10^(-3) kg , q = 6 xx 10^(-2) C, v = 1 //sqrt3 .

An electron (mass =9xx10^(-31)kg , charge= 1.6xx10^(-19)C) enters a magnetic field with velocity 10^(6)m*s^(-1) and starts rotating in a circular path of radius 10 cm. What is the magnetic field ?

An electron has mass 9xx10^(-31)kg and change 1.6xx10^(-19)C is moving with a velocity of 10^(6)m//s , enters a region where magnetic field exists. If it describes a circle of radius 0.10m , the intensity of magnetic field must be

A particle of mass m and charge q enters a magnetic field B perpendicularly with a velocity v , The radius of the circular path described by it will be

A circular plane sheet of radius 10 cm is placed in a uniform electric field of 5xx10^(5) NC^(-1) , making an angle of 60^(@) with the field. Calculate electric flux through the sheet.

A circular plane sheet of radius 10 cm is placed in a uniform electric field of 5xx10^(5) NC^(-1) , making an angle of 60^(@) with the field. Calculate electric flux through the sheet.

A particle of mass m and charge q is incident on xz plane with velocity v in a direction making angle theta with a uniform magnetic field applied along x-axis. The nature of motion performed by the particle is _______ .