[" Calculate the depression in freezing point of water when "10g" of "CH_(2)CH(Cl).COOH" is added to "250],[g" of water."Ka=1.4times10^(-3),Kg=1.86KKgmol^(-1)]

Calculate the depression in freezing point of water when 10 g of CH_(3)CH_(3)CH(CI)COOH is added to 250 g of water. K_(a)=1.4xx10^(-3), K_(f)=1.86 K kg mol^(-1) .

Calculate the depression in the freezing point of water when 10g of CH_(3)CH_(2)CHClCOOH is added to 250g water. K_(a)=1.4xx10^(-3),K_(f)=1.86K kg mol^(-1) .

Calculate the depression in the freezing point of water when 10g of CH_(3)CH_(2)CHClCOOH is add to 250g water. K_(a)=1.4xx10^(-3),K_(f)=1.86K kg mol^(-1) .

Calculate the depression in freezing point of water when 20g of CH_3CH_2CHClCOOH is added to 500g of water. (Given Ka=1.4xx10^(-3)K_f=1.86 )

Calculate the depression in the freezing point of water when 10g of CHM_(3)CHM_(2)CHMClCOOH is add to 250g water. K_(a)=1.4xx10^(-3),K_(f)=1.86K kg mol^(-1) .

Calculate the depression in the freezing point of water when '10 g' of 'CH_3 CH_2 CHClCOOH' is added to '250 g' of water. 'Ka=1.4 xx 10^-3, Kf=1.86Kkgmol^-1'

Calculate the depression in the freezing point of water when 10 g of CH_3CH_2CHClCOOH is added to 250 g of water. K_a = 1.4 x 10^(-3) , K_f = 1.86 K kg moL^(-1) .

Calculate the depression in the freezing point of water when 10 g of CH_3CH_2CHClCOOH is added to 250 g of water. K_a = 1.4xx10^-3 , K_f = 1.86 K kg mol^-1 .

Calculating the depression in the freezing point of water when 10g of CH_3CH_2CHClCOOH is added to 250g of water. Ka= 1.4xx10^-3 , kf =1.86 K kgmol (-1)