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If 2^x=3^y=6^z , then 1/x+1/y+1/z=...

If `2^x=3^y=6^z` , then `1/x+1/y+1/z=`

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If 2^x=3^y=6^(-z) prove that 1/x+1/y+1/z=0

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(2-3x)/(x)+(2-3y)/(y)+(2-3z)/(z)=0 then (1)/(x)+(1)/(y)+(1)/(z)=