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(sin 12^(@)) (sin 48^(@)) (sin 54^(@) ) ...

`(sin 12^(@)) (sin 48^(@)) (sin 54^(@) ) = ?`

A

`1/8`

B

`1/7`

C

`1/6`

D

`1/5`

लिखित उत्तर

Verified by Experts

The correct Answer is:
A

`LHS=``(sin 12^(@)) (sin 48^(@)) (sin 54^(@))`

`=1/2 xx(2 sin 12^(@)``sin 48^(@))xxsin 54^(@)`

`=1/2 xx[cos (12^(@)-48^@)``-cos (12^@ + 48^(@)]``xxsin 54^(@)`

चूंकि `2sinAsinB``=cos(A-B)-cos(A+B)`

`=1/2 xx[cos (-36^@)``-cos (60^(@))]``xx(sqrt5 + 1)/(4)`

चूंकि `sin 54^(@) ``=(sqrt5 + 1)/(4)``=cos36^@`

`=1/2 xx[cos (36^@)``-1/2]``xx(sqrt5 + 1)/(4)`

`=1/2 xx[(sqrt5 + 1)/(4)``-1/2]``xx(sqrt5 + 1)/(4)`

`=1/2 xx[(sqrt5 + 1- 2)/4]``xx(sqrt5 + 1)/(4)`

`=1/2 xx[(sqrt5 -1)/4]``xx(sqrt5 + 1)/(4)`

`=1/2 xx[((sqrt5)^2-1^2]/16]`

`=1/2 xx[(5-1]/16]``=1/2 xx[4/16]`

`=1/8``=RHS`

अतः सिद्ध हुआ।
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